I've had zero time to scrounge or get out and drop-n-haul wood this summer, so I'm having a load delivered. 19-20 cord of log length for $1400., all Lodgepole. I've talked with numerous loggers this summer and most agree that it cost's them about $50. per cord to get the wood out of the hills before final destination. This guy has to drive 1-1/2 hours one way just to get it to me, so I'm thinking this is a pretty fair price.
I've never measured a load to guess what the net result would be, but the lengths are averaged out at 45', and 10"- 16" diam. If the load works out to close to the 19 cord mark, I'll have him drop off another load and I won't have to think about heat for a while. Nor will my deserving neighbors. So...
How do I toss a tape on this incoming load to figure out how much wood is there? Is there a rough formula to throw a flex tape around a load and say -"it's X diam. and Y length, so it should be Z net"? Thanks, JB.
I've never measured a load to guess what the net result would be, but the lengths are averaged out at 45', and 10"- 16" diam. If the load works out to close to the 19 cord mark, I'll have him drop off another load and I won't have to think about heat for a while. Nor will my deserving neighbors. So...
How do I toss a tape on this incoming load to figure out how much wood is there? Is there a rough formula to throw a flex tape around a load and say -"it's X diam. and Y length, so it should be Z net"? Thanks, JB.