Burning question, no pun intended. Am reading through the Jotul technical manual, which interestingly is all in kW, even in the English section. for the F500, the "Nominal heat output is 8,5 kW". Can someone reference me to a magic decoder ring to convert this and other references to Temps and/or BTU's?
Secondly, was comparing the info in the old VC Defiant Encore with the info in the F500 manual. I get it that BTU's may vary based on different conditions, wood type moisture, etc.
The VC DE manual indicates a:
- Range of heat output = 6200-32,000 BTU/hr.
- Max heat output is 47,000 BTU/hr
- Operating at continuous griddle temps of 750 degrees, or higher may cause damage to the stove
For the F500, it is rated at Max 70,000 BTU's/hour. I can find only one reference to what the operating temperature should be kept, and it is listed in the General Manual, under section 8.3, titled "Thermometer". It says, "Persistent overheating of the fireplace (Temperatures of 280 degrees Celcius or more) will hasten the need for replacement parts that are excluded by Warranty."
Conversion from Celcius to Fahrenheit is: 280 C = 560 Farenheit, suggesting not to consistently burn the F500 over 560 degrees Farenheight. Normal max for the VE DC - 750 degrees F, while the F500 is 560 degress 'max'. Okay, well how does an F500 achieve 70, 000 Max heat output, and the DE VC has a Max of 47,000 BTU output, when consideration is given to the operating temps? Trying to compare apples to apples, i.e., VC DE to F500. Is there somehow more BTU heat output from the F500, even though the max operating temp listed is lower than the VC DE? Thanks in advance.