Hey guys- building a woodshed with six posts in a rectangular pattern, 8ft by 16ft with a post every 8ft. I need help with math equation to make sure everything's square. Thanks!
no man said:Ask BrotherBart he will figure it out for you.
BeGreen said:And in the 8 x 16 case, the triangles are not 3-4-5 rule compliant. Different side ratios in that case.
fossil said:...Trigonometry tells us that there is one of all possible right triangles (a right triangle being one with two sides perpendicular to one another, or at a 90-degree angle), which conveniently has sides with lengths in the ratio of 3:4:5. In other words, if you measure out from one corner 3 feet or 3 meters, or three miles or three of Jags' buck lengths, or 3 whatever, and then you measure out 4 of the very same thing on the other side you want to be square with the first, then measure the distance (hypotenuse) of the triangle between those two marks, if you get 5 of the same thing, then you've built a square structure.
BeGreen said:No math needed
The math - side A squared (8'sq. or 64) plus side B squared (16'sq. or 256) equals side C squared, the hypoteneuse in a right triangle (the diagonal). So the diagonal should be the square root of 256 + 64 (320), or 17.89 ft (about 214 7/8").
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